Question

Write the complex number in the form a + bi. 3(cos 270° + i sin 270°)

Answer 1

corresponds to the very bottom of the circle --- is equal to -3i

Answer 2

Given the complex number:
`3(\cos 270^(\circ)+i \sin 270^(\circ))`

Let
`z=3(\cos 270^(\circ)+i \sin 270^(\circ))`

we have to write this complex number in the form of a+ib.

We know :

`\cos 270^(\circ) = 0`

`\sin 270^(\circ) = -1`

Then;

`z = 3(0+i(-1)) = 3(0-i)`

or

`z = 0-3i`

Therefore, the given complex number in the form of a+ib is, 0-3i