Write the complex number in the form a + bi. 3(cos 270° + i sin 270°)

Question

asked May 21, 2018 91.1k views

2 Answers

Idob · Answer 1 · 2018-05-26T15:02:25+0000

Answer:

Given the complex number:
$3(\cos 270^(\circ)+i \sin 270^(\circ))$

Let
$z=3(\cos 270^(\circ)+i \sin 270^(\circ))$

we have to write this complex number in the form of a+ib.

We know :

$\cos 270^(\circ) = 0$

$\sin 270^(\circ) = -1$

Then;

z = 3(0+i(-1)) = 3(0-i)

or

z = 0-3i

Therefore, the given complex number in the form of a+ib is, 0-3i