Question

I need some help with this (and no this is not a test)

Answer 1

You have the following expression:

`a_n=3+2(a_(n-1))^(2)`

consider a1 = 6.

In order to determine the value of a2, consider that if an = a2, then an-1 = a1. Replace these values into the previous sequence formula:

`\begin{gathered} a_2=3+2(a_1)^(2)= \\ 3+2\mleft(6\mright)^2= \\ 3+2(36)= \\ 3+72= \\ 75 \end{gathered}`

Hence, a2 is equal to 75