Given the equation y=-2x^2+1. determine the direction of opening, coordinates of the vertex, Maximum or minimum value and the axis of symmetry

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asked Dec 9, 2018 157k views

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Balazsbalazs · Answer 1 · 2018-12-13T03:57:45+0000

the sign of the term in x^2 is negative so the graph will open downwards.
when x = 0 y = 1
The coordinates of the vertex are (0,1)
the maximum value of the function is 1
and the axis of symmetry ix x = 0 ( the y axis)

Given the equation y=-2x^2+1. determine the direction of opening, coordinates of the vertex, Maximum or minimum value and the axis of symmetry

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