Question

Please help me out with this problem ​

Answer 1

(1/8){7x+(1/5)}

Explanation:

Given that:

(3/4){(5/6)x} - (3/5){-(1/6)} - 2x(-3/8) = ?

= (3/4) * (5/6)x - (3/5){-(1/6)} - 2x(-3/8)

= (5x/8) + (3/5) * (1/6) - 2x(-3/8)

= (5x/8) + 1/(5*2) - 2x(-3/8)

= (5x/8) + (1/10) - 2x(-3/8)

= (5x/8) + (1/10) - x(-3/4)

= (5x/8) + (1/10) +(3x/4)

= (5x/8) + (3x/4) + (1/10)

Take the LCM of the denominator 4 and 8 is 8.

= {(7x*1 + 3x*2)/8} + (1/10)

= {(7x + 6x)/8} + (1/10)

= {(7x)/8} + (1/10)

= (7x/8) + (1/10)

Take the LCM of the denominator 8 and 10 is 40.

= {(7x*5 + 1*1)/40}

= {(35x + 1)/10}

= (7x/8) + (1/40)

= (1/8){7x+(1/5)} Ans.

Please let me know if you have any other questions.

Answer 2

`\rm \longmapsto \: (3)/(4) ( (5x)/(6) ) + ( - 3)/(5) ( ( - 1)/(6) ) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (3)/(4) * (5x)/(6) + ( - 3)/(5) ( ( - 1)/(6) ) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (3 * 5x)/(4 * 6) + ( - 3)/(5) ( ( - 1)/(6) ) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (15x)/(24) + ( - 3)/(5) ( ( - 1)/(6) ) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (5x)/(8) + ( - 3)/(5) ( ( - 1)/(6) ) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (5x)/(8) + (1)/(10) - 2x( ( - 3)/(8) )`

`\sf \longmapsto \: (5x)/(8) + (1)/(10) + (3)/(4) x`

`\sf \longmapsto \: (5x)/(8) + (1)/(10) + (3x)/(8)`

`\sf \longmapsto \: (5x + (4)/(5) + 2 * 3x)/(8)`

`\sf \longmapsto \: (5x + (4)/(5) + 6x)/(8)`

• Combine like terms:

`\sf \longmapsto \: (5x + 6x + (4)/(5) )/(8)`

`\sf \longmapsto \: (11x + (4)/(5) )/(8)`