Question

(m^3p^5divide by n^7)x(m^2n^0p^3divdie bye m^4n^2)^3

Answer 1

convert division to exponent neative
also, n^0=1 so get rid of that nonesense
also we have m^2/m^4 so we are left wiht 1/(m^2) or m^-2

so

`(m^3p^5n^(-7))(p^3m^(-2)n^(-2))^3`=

`(m^3p^5n^(-7))((p^3)^3)((m^(-2))^3)((n^(-2))^3)`=

`(m^3p^5n^(-7))(p^9)(m^(-6))(n^(-6))`=

`(m^3)(p^5)(n^(-7))(p^9)(m^(-6))(n^(-6))`=

`(m^(-3))(p^(14))(n^(-13))`=

`(p^(14))/(m^3n^(13))`