112k views
1 vote
Simplify
(5x^7y^3z^-1)^2x(2xy^-5)^3x(2y^-3z^2)^3

User Sigi
by
8.7k points

1 Answer

5 votes
remember

(abc)^x=(a^x)(b^x)(c^x)
and

(x^m)(x^n)=x^(m+n)
and

(x^m)^n=x^(mn)
and

x^(-m)= (1)/(x^m)
so


(5x^7y^3z^(-1))^2(2xy^(-5))^3(2y^(-3)z^2)^3=

(5^2)((x^7)^2)((y^3)^2)((z^(-1))^2)(2^3)(x^3)((y^(-5))^3)(2^3)((y^(-3))^3)((z^2)^3)=

(25)(x^(14))(y^6)(z^(-2))(8)(x^3)(y^(-15))(8)(y^(-9))(z^6)=

1600x^(17)y^(-18)z^4=

(1600x^(17)z^4)/(y^(18))
User Mikhail Ramendik
by
7.5k points