Answer:
The distance of two complex numbers
= 9.055
Explanation:
Step(i):-
Given that z₁ = 6-3i and z₂ = -3-4i
We know that 'z' represents a point on the argand plane with absicca 'x' and ordinate 'y'
Now given points are ( x₁ , y₁) = (6 ,-3) and (x₂, y₂) = (-3 , -4)
Step(ii):-
The distance of two points

z₁ z₂


=9.055