Question

Let f(x) = 27x5 − 33x4 − 21x3 and g(x) = 3x2. Find f of x over g of x

Answer 1

i am assuming when you write 27x5 u mean "27 times x to the power of 5".

therefore, your answer is 9x3-11x2-7x

Answer 2

`(f(x))/(g(x))=(9x^3-11x-7x`

Explanation:

Given function
`f(x) = 27x^5-33x^4-21x^3` and
`g(x)=3x^2`

We have to find f of x over g of x that is
`(f(x))/(g(x))`

Consider ,

`f(x) = 27x^5-33x^4-21x^3` and
`g(x)=3x^2`

To find
`(f(x))/(g(x))`

Substitute the values for functions, we get,

`(f(x))/(g(x))=(27x^5-33x^4-21x^3)/(3x^2)`

Taking
`3x^2` common from numerator, we get,

`(f(x))/(g(x))=(3x^2(9x^3-11x-7x))/(3x^2)`

Thus,
`3x^2` gets cancel, we get,

`(f(x))/(g(x))=9x^3-11x-7x`

Thus, value of function f of x over g of x is
`9x^3-11x-7x`