Question

If the work put into a lever is 25.0 joules and the work done by the lever is 20.0 joules, what is the efficiency of the lever?

Answer 1

The efficiency is Wout/Win = 25/20

Answer 2

Efficiency of the lever is 80 %.

Step-by-step explanation:

Given that, if the work put into a lever is 25.0 joules and the work done by the lever is 20.0 joules. We need to find the efficiency of the lever. The mathematical expression for the efficiency is given by :

`\eta=(W_o)/(W_i)* 100`

Where

`W_o\ and\ W_i` are output and input work respectively.

`\eta=(20)/(25)* 100`

`\eta=80\%`

So, the efficiency of the lever is 80 %. Hence, this is the required solution.