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According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed? 2H₂S(g) + SO₂(g) → 3S(s) + 2H₂O(l)
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According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed?

2H₂S(g) + SO₂(g) → 3S(s) + 2H₂O(l)

User Nirav Dangi
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1 Answer

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We see that the molar ratio of sulfur to water is:
3 : 2

We first compute the moles of water:
moles = mass / Mr
moles = 37.4 / 18
moles = 2.08

By the ratio, moles of sulfur:
3.12

Mr sulfur = 64

mass = 3.12 x 64
mass = 199.7 grams
User Kumar Saurabh Sinha
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7.1k points
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