Answer:
Point C′ of the image coincides with point E of the preimage.
Point D′ of the image coincides with point F of the preimage.
Explanation:
A translation counterclockwise 60° moves point A to F, F to E, E to D, et cetera. A translation counterclockwise 180° moves any vertex to the opposite vertex, so A moves to D, B to E, C to F and vice versa. Then, a translation counterclockwise 240° is a combination of the two aforementioned translations and moves A to C, F to B, E to A, D to F, C to E and B to D, creating the hexagon A′B′C′D′E′F′ (see figure attached).