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How much water is present in 83.0 g of Li3PO4 * 12H2O?
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How much water is present in 83.0 g of Li3PO4 * 12H2O?

User Roboroads
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Try dividing the 83.0 g by the molar mass of Li3PO4* 12H2O and then multiply that result by a number of H2O moles (12). You should get 3.0027 mol.
User Boran
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