Question

Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt):2 Na(s) + Cl2 (g) > 2 NaCI(s)If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride should form?1. 12.1 grams2. 1.18 x 10^2 grams3. 15.9 grams4. 3.18 x 10^1 grams5. 51.0 grams

Answer 1

`4\text{ : 3.18 }*\text{ 10}^1\text{ grams}`

Step-by-step explanation:

Here, we want to calculate the mass of sodium chloride formed

Firstly, we need to get the number of moles of sodium that reacted

To get this, we divide the mass of sodium by its atomic mass

We have that as:

`(12.5)/(23)\text{ = 0.5435 mole}`

Now, let us get the number of moles of chlorine

From the equation of reaction, 1 mole of sodium produced 1 mole of sodium chloride

Thus, 0.5435 mole of sodium will also produce 0.5435 mole of sodium chloride

To get the mass of sodium chloride formed, we multiply the above number of moles by the molar mass of sodium chloride

The molar mass of sodium chloride is 58.44 g/mol

Thus, the mass of sodium chloride formed will be:

`58.44\text{ }*\text{ 0.5435 = 31.8 g}`