Question

Find the solution to following system of equations A+ 10C = 54 A +9C = 50 A. A=10 C= 4 B. A= 14 C= 4 C. A=4 C= 14 D. A= 10 C= 6

Answer 1

B. A = 14

C = 4

Step-by-step explanation:

The system of equation is:

A + 10C = 54

A + 9C = 50

So, we can solve for A using the first equation:

A + 10C = 54

A + 10C - 10C = 54 - 10C

A = 54 - 10C

Now, we can replace A by (54 - 10C) on the second equation, so:

A + 9C = 50

(54 - 10C) + 9C = 50

54 - 10C + 9C = 50

54 - C = 50

54 - C + C = 50 + C

54 = 50 + C

54 - 50 = 50 + C - 50

4 = C

Then, we can replace C by 4 and calculate A, so:

A = 54 - 10C

A = 54 - 10(4)

A = 54 - 40

A = 14

Therefore, the solution of the system is:

A = 14

C = 4