Question

Howmany Mol MnO3areproducedwhen 4.30 kg of O2completelyreactsaccordingtothebalancedchemicalreaction:2Mn(s)+3O₂(g)→2MnO₃(s)Answer as equation

Answer 1

89.58 moles of MnO3 are produced.

Step-by-step explanation:

1st) From the balanced reaction we know that the relation between O2 and MnO3 is that 3 moles of O2 produces 2 moles of MnO3.

2nd) To build the equation, we must build a path from the given value of 4.30kg of O2 to moles of MnO3. So, it is important to figure out the relations that we need to build the equation.

The order to build the equation is:

• Start with, the given value of ,4.30kg of O2,.

,

• We need to convert kg to grams, so we need the realtion between kg and g: ,1kg=1000g,.

,

• To convert the grams of oxygen to moles, we need to use the molar mass of O2: ,32g/1mol,.

,

• We need to use the relation between O2 and MnO3 from the balanced equation: ,3 moles of O2, produces, 2 moles of MnO3,.

`4.30kg\text{ O}_2*(1000g)/(1kg)*\frac{1mol\text{ O}_2}{32g\text{ O}_2}*\frac{2moles\text{ MnO}_3}{3moles\text{ O}_2}=89.58moles\text{ MnO}_3`

So, 89.58 moles of MnO3 are produced.