Question

A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θA = 36° above the x axis, and the angle θB = 54° below the x axis. 1)

What is the x component of the car’s acceleration when it is at point A

Answer 1

Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s

x component = sine ( 32 ° ) * 20.583 = 10.91 m/s

hope this helps :)