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Four friends were born on consecutive years. The sum of their ages is 62. What is the age of the youngest friend?

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Let, their ages = x , x+1, x+2, x+3

It is given that, x+x+1+x+2+x+3 = 62
4x+6 = 62
4x = 56
x = 56/4
x = 14

In short, Your Answer would be 14 Years

Hope this helps!
User Guilherme Ferreira
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