Question

What is the atomic mass of an element if 4.00 grams of it contains 2.98x1022 atoms ?

Answer 1

Hope this helps you.

Answer 2

Atomic mass of the element = 80.80 amu

Step-by-step explanation:

Given:

Mass of element = 4.00 g

No. of atoms =
`2.98* 10^(22)`

`mol = (No.\ of\ atoms)/(Avogadro's\ no.)`

Avogadro's no. = tex]6.02\times 10^{23}[/tex]

`mol = (No.\ of\ atoms)/(Avogadro's\ no.)`

=
`(2.98* 10^(22))/(6.02* 10^(23)) = 0.0495\ mol`

Formula for moles in the terms of mass and atomic mass

`mol = (Mass\ in\ g)/(Atomic\ mass) \\Atomic\ mass = (Mass\ in\ g)/(mol)`

Atomic mass of the element =
`(4.00)/(0.0495) = 80.80\ amu`

Atomic mass of the element = 80.80 amu