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2 votes
Elimination using multiplication.
3x-5y=14
2x+4y=2

1 Answer

4 votes
3x - 5y = 14
2x + 4y = 2

We multiply the first equation by 2 and the second equation by 3 to obtain:

6x - 10y = 28
6x + 12y = 6

Subtracting the two equations:

-22y = 22
y = -1

Using this in the first equation:
3x - 5(-1) = 14
x = 3

The solution is:
(3 , -1)

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