Question

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative 3. E is at 2, 4. 1.67 −1.33 0.75 −1.25

Answer 1

The answer would be -1.25

Answer 2

The correct option is 4.

Explanation:

It is given that DF and EF form a 1:3 ratio. The coordinates of the end points of the segment DE are D(-3,-3) and E(2,4).

According to the section formula, if a point p divides a line in m:n, then the coordinates of p are

`((mx_2+nx_1)/(m+n),(my_2+ny_1)/(m+n))`

y value for point F is calculated as

`y=((1)y_2+(3)y_1)/(1+3)`

The end points of the segment DE are D(-3,-3) and E(2,4).

`y=((1)(4)+(3)(-3))/(4)`

`y=(4-9)/(4)`

`y=(-5)/(4)`

`y=-1.25`

The y- value for point F is -1.25. Therefore the correct option is 4.