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11 votes
11 votes
Write the sequence {15, 31, 47, 63...} as a function A. A(n) = 16(n-1)B. A(n) = 15 + 16nC. A(n) = 15 + 16(n-1)D. 16n

User Emsr
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1 Answer

16 votes
16 votes

To find the answer, we need to prove for every sequence as:

Answer A.

If n=1 then:

A(1) = 16(1-1) = 16*0 = 0

Since 0 is not in the sequence so, this is not the answer

Answer B.

If n=1 then:

A(1) = 15 + 16*1 = 31

Since 31 is not the first number of the sequence, this is not the answer

Answer D.

If n=1 then:

16n = 16*1 = 16

Since 16 is not in the sequence so, this is not the answer

Answer C.

If n = 1 then:

A(1) = 15 + 16(1-1) = 15

A(2) = 15 + 16(2-1) = 31

A(3) = 15 + 16(3-1) = 47

A(4) = 15 + 16(4-1) = 63

So, the answer is C

Answer: C. A(n) = 15 + 16(n-1)

User Royden
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