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A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.
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A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

User Jeorfevre
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1 Answer

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A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b

10b = 30√2; b = 3√2

sin α = 3√2 / 6; α = 45 degrees

Small angle: 45°; Large angle: 135°
User James Strachan
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