A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

Question

asked Dec 4, 2018 79.4k views

1 Answer

James Strachan · Answer 1 · 2018-12-08T23:46:03+0000

A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b

10b = 30√2; b = 3√2

sin α = 3√2 / 6; α = 45 degrees

Small angle: 45°; Large angle: 135°