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If f(x) = x^3 + 13x^2 + 46 x + 48 and x + 8 is a factor of f(x) find all of the zeroes of f(x) algebraically

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If x + 8 is a factor, we can factor it out from f(x).

f(x) = (x+8)(x²+5x+6)

= (x+8)(x+2)(x+3)

The zeroes of f(x) are -8, -2 and -3.

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