Question

40 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Someone please help this is due tommorrow

For questions 9-10, refer to the figure of the triangle above. The known angles are 44.1° and 47.6°, respectively.

9. Find the measure of angle k. (problem 10; example 2a page 321)

10. Classify this triangle as acute, right, or obtuse. (problem 9; page 320)
For questions 1-4, please refer to the diagram below in which two parallel lines are cut by transversal.



1. Please name two pairs of corresponding angles.

2. Name two pairs of alternate interior angles.

3. Find the measure of angle 7.

4. Find a measure of angle 8.

look at the first graph



5. Find the sum of angles KMA and YMA.

6. Solve for the value of x.

7. Find the measure of angle KMP.

8. Find the measure of the complement of angle KMA.
look at the second graph↓

Answer 1

The answer would be 57 degrees

Explanation:

Answer 2

I am guessing at # 9 because there is no picture...but interior angles of a triangle add up to 180

so if 1 angle is 44.1 and the other angle is 47.6, then the third angle is :
180 - (44.1 + 47.6) = 180 - 91.7 = 88.3.....and this is an acute triangle
==================
2 pairs of corresponding angles : <2 and < 6.......< 1 and < 5
2 pairs of alternate interior angles : < 3 and < 6....< 4 and < 5
m < 7 = 106
m < 8 = 74
=================
< KMA + < YMA = 180

2x - 3 + 7x + 21 = 180
9x + 18 = 180
9x = 180 - 18
9x = 162
x = 162/9
x = 18

m< KMP = 7x + 21 = 7(18) + 21 = 147

complement of < KMA is (90 - m < KMA) = 90 - 33 = 57 degrees