Question

Please someone help me. I've been stuck for about an hour

Answer 1

`\bf f(x)=\cfrac{1}{2}x+4\qquad inverse\implies x=\cfrac{1}{2}f(x)+4 \\\\ \textit{now, solving for f(x)} \\\\ x-4=\cfrac{f(x)}{2}\implies 2(x-4)=f(x)\iff f^(-1)(x) \\\\ f^(-1)(4)=2(\boxed{4}-4)\implies f^(-1)(4)=2(0)\implies f^(-1)(4)=0`