Question

You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2

Answer 1

PLEASE DELETE THIS ANSWER. ANSWERED A DIFFERENT QUESTION BUT POSTED IT HERE.

Explanation:

Answer 2

By the polynomial remainder theorem, the remainder upon dividing
`p(x)` by
`x-3` will be the value of
`p(3)`.

... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have


`(x^4-6x^3-4x^2-6x-2)/(x-3)=x^3-3x^2-13x-45-(137)/(x-3)`

which means
`p(3)=-137`.