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14. Given: JM bisects JL JM perpendicular to KLProve: TRIANGLE JMK congruent to TRIANGLE JML

14. Given: JM bisects JL JM perpendicular to KLProve: TRIANGLE JMK congruent to TRIANGLE-example-1
User Nick Fortescue
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1 Answer

17 votes
17 votes

1) is already written, so we start with the second line.

2)

JM is parallel to KL ----> Given

3) ∠KML = ∠JML ----> They are angles on two perpendicular lines, and Since JM bisects LK, they are equal.

4) ∠KJL=∠MKL ---> Since JM bisects ∠J, the angles KJL and MKL are equal

5) ∠JKM=∠JLM ----> Since 3) and 4), the angles JKM and JLM must also be equal so that the sum of internal angles of each triangle will be 180°

Thus: Triangle JMK is congruent to triangle JML

User OrenD
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