Question

Haley was jumping on the trampoline at her house. As her socks rubbed against the trampoline, they became charged. If a small piece of lint with a charge of +4.55 E -21 C is attracted to the socks by a force of 1.5 E -9 N, what is the magnitude of the electric field at this location?

Answer 1

The magnitude of the electric field (E) at a certain location is calculated by dividing the force (F) by the charge (C). Mathematically,

E = F / C

E = (1.5 x 10^-9 N) / (4.55 x 10^-21 C)
E = 3.30 x 10^11 N/C

Therefore, the magnitude of the electric field is equal to 3.30 x 10^11 N/C.