Question

Suppose you have a container divided by a membrane that is permeable to water but not to sugar. Side A has a 10% sugar solution. Side B has a 40% sugar solution. Both start out at 10 cm in height. Over time, the height of one side drops to 7 Cm and the height of the other side increases to 13 cm. Which side of the container is now at 7 cm? Explain.

Answer 1

The side of the container that is now at 7 cm is Side A, which originally had a 10% sugar solution. When a selectively permeable membrane separates two solutions of different concentrations, water molecules will move through the membrane from the side of higher water concentration to the side of lower water concentration in a process called osmosis.

Step-by-step explanation:

The side of the container that is now at 7 cm is Side A, which originally had a 10% sugar solution.

When a selectively permeable membrane separates two solutions of different concentrations, water molecules will move through the membrane from the side of higher water concentration to the side of lower water concentration in a process called osmosis. In this case, the 10% sugar solution on Side A has a higher water concentration compared to the 40% sugar solution on Side B, causing water to move from Side A to Side B.

As Side A loses water molecules, its height decreases, while Side B gains water molecules and its height increases.

Answer 2

the movement of water is from A to B !!

thus making equilibrium water in B must be more so that water is balanced in both !!

thus the water in B will be 13 and in A , 7 cm !!

so , the answer is A !! it has 7 cm of water !!