Which function has a vertex at the origin A) f(x)= (x+4)^2 B) f(x)= x(x-4) C) f(x)= (x-4)(x+4) D) f(x)= x^2

asked Mar 5, 2018 62.6k views

2 votes

Which function has a vertex at the origin

A) f(x)= (x+4)^2
B) f(x)= x(x-4)
C) f(x)= (x-4)(x+4)
D) f(x)= x^2

by Oral

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3 votes

Answer:

Explanation:

i love helping people so the answer is D

Tim Harper answered Mar 6, 2018

5.3k points

6 votes

D) f(x)= x^2

prove :
f'(x) = 2x ;
f'(x) = 0 at, x= 0

BarrieK answered Mar 9, 2018

5.7k points

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