Question

Does anyone know how to do the rest?​

Answer 1

Answer/Step-by-step explanation:

Given:

`(4)/(x) - (3)/(y) = 1` ---› Equation 1

`(8)/(x) + (9)/(y) = 7` ---› Equation 2

Solution:

✔️Equation 1 × 3:

`(4)/(x)*3 + (3)/(y)*3 = 1*3`

`(12)/(x) + (9)/(y) = 3` ---› Equation 3.

✔️Equation 2 + Equation 3:

`(8)/(x) + (9)/(y) = 7` ---› Equation 2

`(12)/(x) + (9)/(y) = 3` ---› Equation 3.

Thus:

`(-4)/(x) = 10`

Cross multiply

`10x = -4`

Divide both sides by 10

`x = -(4)/(10)`

`x = -(2)/(5)`

✔️Find y:

Substitute x = -2/5 into equation 1

`(4)/(x) - (3)/(y) = 1` ---› Equation 1

`(4)/((-2)/(5)) - (3)/(y) = 1`

`\frac{4}*{(5)/(-2)} - (3)/(y) = 1`

`-10 - (3)/(y) = 1`

Add 10 to both sides

`- (3)/(y) = 1 + 10`

`(-3)/(y) = 11`

Cross multiply

`11y = -3`

Divide both sides by 11

`y = -(3)/(11)`