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When an ion accelerates through a potential difference of 2160 V its electric potential energy decreases by 3.46×10−16 J . What is the charge on the ion?
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Sep 22, 2018
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When an ion accelerates through a potential difference of 2160 V its electric potential energy decreases by 3.46×10−16 J . What is the charge on the ion?
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Georg Mavridis
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We do as follows:
energy = charge x voltage change .
Let q be the charge then E = q V
and solving for q we have
q = E / V = -1.37e-5J / 2850V =
-4.81x10-9 C
Hope this answers the question. Have a nice day.
Dan Stevens
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Sep 26, 2018
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Dan Stevens
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