Question

During a construction project, heavy rain filled construction cones with water. The diameter of a cone is 12 in. and the height is 27 in. What is the volume of the water that filled one cone?

Answer 1

volume of a cone = πr^2(h/3)
r=6
h=27

v = π(6^2)27/3
v = π (36)(9)

v=π324 in. cubed
or
v=1,017.36 in. cubed

Answer 2

the volume of the water that filled one cone is 1017.36 in³ approximately

Explanation:

To find the volume of water that filled the a cone, we will use the formula;

V = π r²
`(h)/(3)`

π is a constant

r is the radius of the cone

h is the height

V = volume of the cone.

From the question given;

Diameter of a cone is 12 in., but radius id half of diameter, this implies r=d/2 = 12/2 = 6 in.

h = 27 and π≈3.14

We can now proceed to insert the values into the formula;

V = π r²
`(h)/(3)`

≈ 3.14 × (6)² ×
`(27)/(3)`

≈ 3.14×36×9

≈1017.36 in³

Therefore the volume of the water that filled one cone is 1017.36 in³ approximately