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Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS HELP
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Find the dimensions of a rectangular piece of property that has a perimeter of 610 feet if the length is twenty feet more than two times the width

PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS HELP

User Isaac To
by
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1 Answer

6 votes
ALGEBRA M8 SOZ

Length = L, Width = W

L = 20 + 2W,
2L + 2W = 610.

then u gotta do some inspiring expression-algebra-maths stuff to work it out :)
User Clangon
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