Answer:
Explanation:
Given is a quadrilateral EFGH inscribed in a circle with centre J.
Consider angle E, which is subtended by minor arc FGH.
Hence angle E = half of angle FGH (by subtended angles theorems for circles)
Similarly G is the angle subtended by major arc FGH
angle G = half of angle subtended by major arc FEH
Since total angle around J is 360 degrees we have
angle subended by minor and major arc add to 360
Consequently, angle E + angle G = 1/2 (360) = 180
Hence E and G are supplementary