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Two sound waves (wave X and wave Y) are moving through a medium at the same speed. If wave X has a greater frequency than wave Y, then wave X

A.
has a lower amplitude.
B.
has a shorter wavelength.
C.
has a longer wavelength.
D.
has a greater amplitude.

2 Answers

2 votes

Answer:

shorter wavelength

Step-by-step explanation:

For waves moving at the same speed, when frequency increases, wavelength decreases. And when frequency increases, wavelength decreases.

Since wave X has a greater frequency and is moving at the same speed as wave Y, it must have a shorter wavelength.

User Frameworksnow
by
7.3k points
2 votes

Answer:

Wave X has a shorter wavelength.

Step-by-step explanation:

It is given that, two sound waves (wave X and wave Y) are moving through a medium at the same speed.

Speed of a wave is given by :


v=\\u* \lambda

Where,


\\u is frequency


\lambda is wavelength

The relation between the frequency and the wavelength is inverse. Wave X has greater frequency than Y, then wave X has a shorter wavelength.

Hence, the correct option is (B) "has a shorter wavelength".

User Mike Gorski
by
6.6k points