Question

9.Solve the differential equation: dy/dx = 4y^2 x1/3

A.1/y = 3x3/4 + C

B.1/y = 3x4/3 + C /y2

C. -1/y2 = 3x4/3 + C/y2

D. -2/y2 =3x4/3 + C/y2

Answer 1

[tex] \frac{dy}{dx}=4 y^{2}* \frac{1}{3}