Question

Algebra 2 question..

Answer 1

We are supposed to solve the equation

`6(2x-1)-12=3(7x+4)`

Here, we need to apply the distributive laws on both sides.

Comment: The distributive laws say that

`a(b+c)=ab+ac\text{ and }(b+c)a=ba+ca`

Using this comment we get

`6(2x-1)=6(2x)+6(-1)=12x-6`
`3(7x+4)=3(7x)+3(4)=21x+12`

Then, our equation becomes

`(12x-6)-12=21x+12`
`12x-18=21x+12`

Now, let's apply the rule: terms with x on the right-hand side, and the rest on the left-hand side, to obtain

`-18-12=21x-12x`
`-30=9x`
`x=(-30)/(9)=-(10)/(3)`