Question

I need help finding the passing adjusted grade of 70A=10R^1/2

Answer 1

Given:

Passing grade = 70

Formula for adjusted grade, A:

`A=10R^{(1)/(2)}`

Given a passing adjusted grade of 70, let's find the raw score, R.

To solve for R, substitute 70 for A and solve for R.

We have:

`\begin{gathered} 70=10R^{(1)/(2)} \\ \end{gathered}`

Divide both sides by 10:

`\begin{gathered} (70)/(10)=\frac{10R^{(1)/(2)}}{10} \\ \\ 7=R^{(1)/(2)} \end{gathered}`

Take the square of both sides:

`\begin{gathered} 7^2=(R^{(1)/(2)})^2 \\ \\ 7^2=R^{(1)/(2)*2} \\ \\ 49=R^1 \\ \\ 49=R \\ \\ R=49 \end{gathered}`

Therefore, the raw score a student would need to have a passing adjusted grade of 70 is 49

ANSWER:

49