Question

If Line BC is equal to 3x + 47, Line DE is equal to 10 and Line BD is equal to 27 + x, find Line CE

Answer 1

`\bf \overline{BD}+\overline{DE}=\overline{BE} \\\\ now\qquad \begin{cases} \overline{BE}-\overline{BC}=\overline{CE} \\\\meaning\\\\ (\overline{BD}+\overline{DE})-\overline{BC}=\overline{CE} \end{cases} \\\\ or\qquad \\\\ \begin{cases} BD=27+x\\ DE=10\\ BC=3x+47 \end{cases}\implies [(27+x)+(10)]-[3x+47]=\overline{CE}`