solve each
3x+5≤-1
minus 5 both sides
3x≤-6
divide 3
x≤-2
other
-2x-7≥5
add 7 to both sides
-2x≥12
divide both sides by -2 and flip sign
x≤-6
we got
x≤-2 or x≤-6
so since x≤-6 is actually inside the solution set of x≤-2, just shade from x≤-2
put dot at x=-2 and shade to left