Let f(x)=9-x^2,g(x)=3-x. Find (f-g)(x)

asked May 28, 2018 193k views

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$(f-g)(x)=9-x^2-(3-x)\\ (f-g)(x)=9-x^2-3+x\\ (f-g)(x)=-x^2+x-6\\ (f-g)(x)=x^2-x+6\\ (f-g)(x)=(x-3)(x+2)\\ x=3\\x=-2$

Padmalochan answered Jun 2, 2018

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