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Find the inverse of:f (x) = 4x3 + 1

User PMan
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1 Answer

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18 votes

1. replace f(x) with y


y=4x^3+1

2. Replace every x with a y and replace every y with an x


x=4y^3+1

3. Solve for y:


\begin{gathered} 4y^3=x-1 \\ y^3=(x-1)/(4) \\ y=\sqrt[3]{(x-1)/(4)} \end{gathered}

4. Replace y with f−1(x):


f^(-1)(x)=\sqrt[3]{(x-1)/(4)}

User NightOwlPrgmr
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