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What is the logarithmic form of the equation e2x ≈ 1732?
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What is the logarithmic form of the equation e2x ≈ 1732?

User PandemoniumSyndicate
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Answer:

ln 1732 = 2x

User Wafeeq
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e2x ≈ 1732, lne2x ≈ ln 1732 and 2xlne= ln 1732, but lne=1, finally x=(1/2) ln1732
User Tliokos
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