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Let f(x) = 2x + 8, 9(x) = x2 + 2x – 8, and h(x) = 3x - 6. Perform the indicated operation. (Simplify as far as possible.) (h. f)(3) = =

User Rev
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\begin{gathered} (3x-6)\cdot(2x+8) \\ 6x^2+24x-12x-48 \\ 6x^2+12x-48 \\ \end{gathered}

x=3


\begin{gathered} 6\cdot3^2+12\cdot3-48 \\ 6\cdot9+36-48 \\ 54+36-48=42 \end{gathered}

User Saurabh Solanki
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