Question

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K? Use mc031-1.jpg and mc031-2.jpg.

Answer 1

28.2 kPa -----------

Answer 2

Answer: The pressure of an ideal gas 0.278 atm.

Step-by-step explanation:

Volume of the ideal gas ,V = 35.5 L

Pressure of an ideal gas,P = 0.138 atm

Temperature of an ideal gas = 223 K

Number of moles of an ideal gas = 0.540 mol

Ideal gas equation is given as:

`PV=nRT`

`P=(n)/(V)* RT=(0.540 mol)/(35.5 L)* 0.0820 atm l/mol K* 223 K`

P = 0.278 atm

The pressure of an ideal gas 0.278 atm.