Question

A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the force exerted by the pump on the water?

Answer 1

Power = force x velocity
3.4 x 10^2 = force x 7.5 x 10^-2

Force = 3.4 x 10^2
--------------------
7.5 x 10^-2

= 4533.33 N

Hope this helps!!

Answer 2

Answer : The force exerted by the pump on the water is, 4533.33 N

Solution :

Power : It is defined as the work done in per unit time.

Formula used :

`P=F* V\\\\F=(P)/(V)`

where,

P = power =
`3.4* 10^2watts`

V = velocity =
`7.5* 10^(-2)m/s`

F = force

Now put all the given values in the above formula, we get the force exerted by the pump on water.

`F=(3.4* 10^2watts)/(7.5* 10^(-2)m/s)=4533.33N`

Therefore, the force exerted by the pump on the water is, 4533.33 N