I need help with number 14

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asked Jan 1, 2018 164k views

2 Answers

Akroma · Answer 1 · 2018-01-02T10:00:19+0000

Al3+ & O2-
Using the cross method this is easy to change into the ionic compound.
The number in front of the charge of the opposite ion will be the subscrpit.
so is would be Al2O3 (with those numbers being subscrpit)

I need help with number 14

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