Question

What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?

Answer 1

The formula we use would be the graham's law. We do as follows:

E_Kr / E_Ne = sqrt ( M_Ne / M_Kr)

= sqrt ( 20.1797 g/mol / 83.798 g/mol )
= sqrt (0.24081)
= 0.4907

Hope this answers the question. Have a nice day.

Answer 2

Answer: The ratio of effusion rates of krypton and neon is 0.49

Step-by-step explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

`\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}`

We are given:

Molar mass of Neon = 20.18 g/mol

Molar mass of Krypton = 83.80 g/mol

By taking their ratio, we get:

`(Rate_(Kr))/(Rate_(Ne))=\sqrt{(M_(Ne))/(M_(Kr))}`

`(Rate_(Kr))/(Rate_(Ne))=\sqrt{(20.18)/(83.80)}\\\\(Rate_(Kr))/(Rate_(Ne))=0.49`

Hence, the ratio of rate of effusion of krypton and neon will be 0.49