How to solve 8x^3-27=0

asked Sep 4, 2018 108k views

2 votes

by Jeem

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5 votes

8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2

Potr Czachur answered Sep 7, 2018

5.6k points

0 votes

Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)

Gok Demir answered Sep 11, 2018

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