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How to solve 8x^3-27=0

User Jeem
by
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5 votes
8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2
User Potr Czachur
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Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)
User Gok Demir
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